3.18.31 \(\int \frac {(a+b x)^{3/2}}{\sqrt [5]{c+d x}} \, dx\) [1731]

Optimal. Leaf size=74 \[ \frac {2 (a+b x)^{5/2} \sqrt [5]{\frac {b (c+d x)}{b c-a d}} \, _2F_1\left (\frac {1}{5},\frac {5}{2};\frac {7}{2};-\frac {d (a+b x)}{b c-a d}\right )}{5 b \sqrt [5]{c+d x}} \]

[Out]

2/5*(b*x+a)^(5/2)*(b*(d*x+c)/(-a*d+b*c))^(1/5)*hypergeom([1/5, 5/2],[7/2],-d*(b*x+a)/(-a*d+b*c))/b/(d*x+c)^(1/
5)

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Rubi [A]
time = 0.02, antiderivative size = 74, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {72, 71} \begin {gather*} \frac {2 (a+b x)^{5/2} \sqrt [5]{\frac {b (c+d x)}{b c-a d}} \, _2F_1\left (\frac {1}{5},\frac {5}{2};\frac {7}{2};-\frac {d (a+b x)}{b c-a d}\right )}{5 b \sqrt [5]{c+d x}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a + b*x)^(3/2)/(c + d*x)^(1/5),x]

[Out]

(2*(a + b*x)^(5/2)*((b*(c + d*x))/(b*c - a*d))^(1/5)*Hypergeometric2F1[1/5, 5/2, 7/2, -((d*(a + b*x))/(b*c - a
*d))])/(5*b*(c + d*x)^(1/5))

Rule 71

Int[((a_) + (b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)/(b*(m + 1)*(b/(b*c
- a*d))^n))*Hypergeometric2F1[-n, m + 1, m + 2, (-d)*((a + b*x)/(b*c - a*d))], x] /; FreeQ[{a, b, c, d, m, n}
, x] && NeQ[b*c - a*d, 0] &&  !IntegerQ[m] &&  !IntegerQ[n] && GtQ[b/(b*c - a*d), 0] && (RationalQ[m] ||  !(Ra
tionalQ[n] && GtQ[-d/(b*c - a*d), 0]))

Rule 72

Int[((a_) + (b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> Dist[(c + d*x)^FracPart[n]/((b/(b*c - a*d)
)^IntPart[n]*(b*((c + d*x)/(b*c - a*d)))^FracPart[n]), Int[(a + b*x)^m*Simp[b*(c/(b*c - a*d)) + b*d*(x/(b*c -
a*d)), x]^n, x], x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[b*c - a*d, 0] &&  !IntegerQ[m] &&  !IntegerQ[n] &&
(RationalQ[m] ||  !SimplerQ[n + 1, m + 1])

Rubi steps

\begin {align*} \int \frac {(a+b x)^{3/2}}{\sqrt [5]{c+d x}} \, dx &=\frac {\sqrt [5]{\frac {b (c+d x)}{b c-a d}} \int \frac {(a+b x)^{3/2}}{\sqrt [5]{\frac {b c}{b c-a d}+\frac {b d x}{b c-a d}}} \, dx}{\sqrt [5]{c+d x}}\\ &=\frac {2 (a+b x)^{5/2} \sqrt [5]{\frac {b (c+d x)}{b c-a d}} \, _2F_1\left (\frac {1}{5},\frac {5}{2};\frac {7}{2};-\frac {d (a+b x)}{b c-a d}\right )}{5 b \sqrt [5]{c+d x}}\\ \end {align*}

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Mathematica [A]
time = 10.03, size = 73, normalized size = 0.99 \begin {gather*} \frac {2 (a+b x)^{5/2} \sqrt [5]{\frac {b (c+d x)}{b c-a d}} \, _2F_1\left (\frac {1}{5},\frac {5}{2};\frac {7}{2};\frac {d (a+b x)}{-b c+a d}\right )}{5 b \sqrt [5]{c+d x}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x)^(3/2)/(c + d*x)^(1/5),x]

[Out]

(2*(a + b*x)^(5/2)*((b*(c + d*x))/(b*c - a*d))^(1/5)*Hypergeometric2F1[1/5, 5/2, 7/2, (d*(a + b*x))/(-(b*c) +
a*d)])/(5*b*(c + d*x)^(1/5))

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Maple [F]
time = 0.01, size = 0, normalized size = 0.00 \[\int \frac {\left (b x +a \right )^{\frac {3}{2}}}{\left (d x +c \right )^{\frac {1}{5}}}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)^(3/2)/(d*x+c)^(1/5),x)

[Out]

int((b*x+a)^(3/2)/(d*x+c)^(1/5),x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^(3/2)/(d*x+c)^(1/5),x, algorithm="maxima")

[Out]

integrate((b*x + a)^(3/2)/(d*x + c)^(1/5), x)

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^(3/2)/(d*x+c)^(1/5),x, algorithm="fricas")

[Out]

integral((b*x + a)^(3/2)/(d*x + c)^(1/5), x)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (a + b x\right )^{\frac {3}{2}}}{\sqrt [5]{c + d x}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)**(3/2)/(d*x+c)**(1/5),x)

[Out]

Integral((a + b*x)**(3/2)/(c + d*x)**(1/5), x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^(3/2)/(d*x+c)^(1/5),x, algorithm="giac")

[Out]

integrate((b*x + a)^(3/2)/(d*x + c)^(1/5), x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (a+b\,x\right )}^{3/2}}{{\left (c+d\,x\right )}^{1/5}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*x)^(3/2)/(c + d*x)^(1/5),x)

[Out]

int((a + b*x)^(3/2)/(c + d*x)^(1/5), x)

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